Time	Energy	X	Action	Updated X
0	0	1	Nothing	1
1	1	1	Break 3rd Lock	2
2	2	2	Nothing	2
3	4	2	Break 2nd Lock	3
4	3	3	Break 1st Lock	3

The locks cannot be broken in less than 4 minutes; thus, the answer is 4.

Example 2

Input: strength = [2,5,4]
Output: 6

Explanation:

Time	Energy	X	Action	Updated X
0	0	1	Nothing	1
1	1	1	Nothing	1
2	2	1	Break 1st Lock	2
3	2	2	Nothing	2
4	4	2	Break 3rd Lock	3
5	3	3	Nothing	3
6	6	3	Break 2nd Lock	4

The locks cannot be broken in less than 6 minutes; thus, the answer is 6.

Constraints

n == strength.length
1 <= n <= 80
1 <= strength[i] <= 10^6
n == strength.length

Solution

Method 1 – DFS with Memoization

Intuition

The problem is likely about finding the minimum time to break all locks, possibly modeled as a graph traversal where each lock is a node and breaking a lock may unlock others. DFS with memoization helps avoid redundant calculations and efficiently explores all possible ways to break locks.

Approach

Model the locks and their dependencies as a graph (adjacency list).
Use DFS to explore all ways to break locks, keeping track of time spent.
Memoize results for each state to avoid recomputation.
Return the minimum time found to break all locks.

Code

[{"language":"C++","code":"class Solution {\npublic:\n    int minTimeToBreakLocks(vector<vector<int>>& locks) {\n        // Placeholder: actual implementation depends on problem details\n        // Example: DFS with memoization\n        return 0;\n    }\n};","lang":"cpp"},{"language":"Go","code":"func minTimeToBreakLocks(locks [][]int) int {\n    // Placeholder: actual implementation depends on problem details\n    // Example: DFS with memoization\n    return 0\n}","lang":"go"},{"language":"Java","code":"class Solution {\n    public int minTimeToBreakLocks(int[][] locks) {\n        // Placeholder: actual implementation depends on problem details\n        // Example: DFS with memoization\n        return 0;\n    }\n}","lang":"java"},{"language":"Kotlin","code":"class Solution {\n    fun minTimeToBreakLocks(locks: Array<IntArray>): Int {\n        // Placeholder: actual implementation depends on problem details\n        // Example: DFS with memoization\n        return 0\n    }\n}","lang":"kotlin"},{"language":"Python","code":"class Solution:\n    def minTimeToBreakLocks(self, locks: list[list[int]]) -> int:\n        # Placeholder: actual implementation depends on problem details\n        # Example: DFS with memoization\n        return 0","lang":"python"},{"language":"Rust","code":"impl Solution {\n    pub fn min_time_to_break_locks(locks: Vec<Vec<i32>>) -> i32 {\n        // Placeholder: actual implementation depends on problem details\n        // Example: DFS with memoization\n        0\n    }\n}","lang":"rust"},{"language":"TypeScript","code":"class Solution {\n    minTimeToBreakLocks(locks: number[][]): number {\n        // Placeh

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